B3Cr5
1 compound has this formula on CompoundList.
- Molar mass
- 292.41g/mol
- Monoisotopic mass
- 292.7305Da
- Atoms
- 8
- Elements
- 2
The formula B3Cr5 describes a molecule made of 3 boron atoms and 5 chromium atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- B Boron × 311.09%10.81 × 3 = 32.430 g/mol
- Cr Chromium × 588.91%51.996 × 5 = 259.980 g/mol
Compounds with the formula B3Cr5
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of B3Cr5?
The molar mass of B3Cr5 is 292.41 g/mol, calculated from standard atomic weights for 3 boron atoms and 5 chromium atoms. The monoisotopic mass is 292.7305 Da.
How many compounds have the formula B3Cr5?
CompoundList lists 1 compound with the molecular formula B3Cr5, including Chromium boride (Cr5B3). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.