BF3HKO
We do not list any compound with this exact formula yet.
- Molar mass
- 123.91g/mol
- Atoms
- 7
- Elements
- 5
The formula BF3HKO describes a molecule made of 1 boron atom, 3 fluorine atoms, 1 hydrogen atom, 1 potassium atom and 1 oxygen atom. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- B Boron × 18.72%10.81 × 1 = 10.810 g/mol
- F Fluorine × 346.00%18.998 × 3 = 56.994 g/mol
- H Hydrogen × 10.81%1.008 × 1 = 1.008 g/mol
- K Potassium × 131.55%39.098 × 1 = 39.098 g/mol
- O Oxygen × 112.91%15.999 × 1 = 15.999 g/mol
Compounds with the formula BF3HKO
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
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Frequently asked questions
What is the molar mass of BF3HKO?
The molar mass of BF3HKO is 123.91 g/mol, calculated from standard atomic weights for 1 boron atom, 3 fluorine atoms, 1 hydrogen atom, 1 potassium atom and 1 oxygen atom.