BF4NO2
1 compound has this formula on CompoundList.
- Molar mass
- 132.81g/mol
- Monoisotopic mass
- 132.9958Da
- Atoms
- 8
- Elements
- 4
The formula BF4NO2 describes a molecule made of 1 boron atom, 4 fluorine atoms, 1 nitrogen atom and 2 oxygen atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- B Boron × 18.14%10.81 × 1 = 10.810 g/mol
- F Fluorine × 457.22%18.998 × 4 = 75.992 g/mol
- N Nitrogen × 110.55%14.007 × 1 = 14.007 g/mol
- O Oxygen × 224.09%15.999 × 2 = 31.998 g/mol
Compounds with the formula BF4NO2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of BF4NO2?
The molar mass of BF4NO2 is 132.81 g/mol, calculated from standard atomic weights for 1 boron atom, 4 fluorine atoms, 1 nitrogen atom and 2 oxygen atoms. The monoisotopic mass is 132.9958 Da.
How many compounds have the formula BF4NO2?
CompoundList lists 1 compound with the molecular formula BF4NO2, including Nitronium tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.