BNa3O3
1 compound has this formula on CompoundList.
- Molar mass
- 127.78g/mol
- Monoisotopic mass
- 127.9634Da
- Atoms
- 7
- Elements
- 3
The formula BNa3O3 describes a molecule made of 1 boron atom, 3 sodium atoms and 3 oxygen atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- B Boron × 18.46%10.81 × 1 = 10.810 g/mol
- Na Sodium × 353.98%22.99 × 3 = 68.970 g/mol
- O Oxygen × 337.56%15.999 × 3 = 47.997 g/mol
Compounds with the formula BNa3O3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of BNa3O3?
The molar mass of BNa3O3 is 127.78 g/mol, calculated from standard atomic weights for 1 boron atom, 3 sodium atoms and 3 oxygen atoms. The monoisotopic mass is 127.9634 Da.
How many compounds have the formula BNa3O3?
CompoundList lists 1 compound with the molecular formula BNa3O3, including Boric acid, sodium salt. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.