BaO3Ru
1 compound has this formula on CompoundList.
- Molar mass
- 286.40g/mol
- Monoisotopic mass
- 287.7943Da
- Atoms
- 5
- Elements
- 3
The formula BaO3Ru describes a molecule made of 1 barium atom, 3 oxygen atoms and 1 ruthenium atom. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- Ba Barium × 147.95%137.33 × 1 = 137.330 g/mol
- O Oxygen × 316.76%15.999 × 3 = 47.997 g/mol
- Ru Ruthenium × 135.29%101.07 × 1 = 101.070 g/mol
Compounds with the formula BaO3Ru
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of BaO3Ru?
The molar mass of BaO3Ru is 286.40 g/mol, calculated from standard atomic weights for 1 barium atom, 3 oxygen atoms and 1 ruthenium atom. The monoisotopic mass is 287.7943 Da.
How many compounds have the formula BaO3Ru?
CompoundList lists 1 compound with the molecular formula BaO3Ru, including Barium ruthenium trioxide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.