Bi2Mn4O10
1 compound has this formula on CompoundList.
- Molar mass
- 797.70g/mol
- Monoisotopic mass
- 797.6621Da
- Atoms
- 16
- Elements
- 3
The formula Bi2Mn4O10 describes a molecule made of 2 bismuth atoms, 4 manganese atoms and 10 oxygen atoms. It is written in Hill notation: with no carbon present, every element is listed in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- Bi Bismuth × 252.40%208.98 × 2 = 417.960 g/mol
- Mn Manganese × 427.55%54.938 × 4 = 219.752 g/mol
- O Oxygen × 1020.06%15.999 × 10 = 159.990 g/mol
Compounds with the formula Bi2Mn4O10
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of Bi2Mn4O10?
The molar mass of Bi2Mn4O10 is 797.70 g/mol, calculated from standard atomic weights for 2 bismuth atoms, 4 manganese atoms and 10 oxygen atoms. The monoisotopic mass is 797.6621 Da.
How many compounds have the formula Bi2Mn4O10?
CompoundList lists 1 compound with the molecular formula Bi2Mn4O10, including Bismuth manganese oxide (BiMn2O5). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.