CompoundList
Molecular formula

C10H10FN5

10 compounds have this formula on CompoundList.

Molar mass
219.22g/mol
Monoisotopic mass
219.0920Da
Atoms
26
Elements
4
Rings plus double bonds
8

The formula C10H10FN5 describes a molecule made of 10 carbon atoms, 10 hydrogen atoms, 1 fluorine atom and 5 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1054.79%
    12.011 × 10 = 120.110 g/mol
  • H Hydrogen × 104.60%
    1.008 × 10 = 10.080 g/mol
  • F Fluorine × 18.67%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 531.95%
    14.007 × 5 = 70.035 g/mol
Look up another formula

Compounds with the formula C10H10FN5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 10 of 10 compounds

Frequently asked questions

What is the molar mass of C10H10FN5?

The molar mass of C10H10FN5 is 219.22 g/mol, calculated from standard atomic weights for 10 carbon atoms, 10 hydrogen atoms, 1 fluorine atom and 5 nitrogen atoms. The monoisotopic mass is 219.0920 Da.

How many compounds have the formula C10H10FN5?

CompoundList lists 10 compounds with the molecular formula C10H10FN5, including 3-(5-Cyclopropyl-1H-1,2,3,4-tetrazol-1-yl)-4-fluoroaniline, 5-(5-Cyclopropyl-1H-1,2,3,4-tetrazol-1-yl)-2-fluoroaniline, 4-(2-Fluoro-5-methylpyridin-3-yl)-6-methyl-1,3,5-triazin-2-amine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C10H10FN5?

C10H10FN5 has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.