CompoundList
Molecular formula

C10H11BrClF2N

4 compounds have this formula on CompoundList.

Molar mass
298.55g/mol
Monoisotopic mass
296.9731Da
Atoms
26
Elements
6
Rings plus double bonds
4

The formula C10H11BrClF2N describes a molecule made of 10 carbon atoms, 11 hydrogen atoms, 1 bromine atom, 1 chlorine atom, 2 fluorine atoms and 1 nitrogen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1040.23%
    12.011 × 10 = 120.110 g/mol
  • H Hydrogen × 113.71%
    1.008 × 11 = 11.088 g/mol
  • Br Bromine × 126.76%
    79.904 × 1 = 79.904 g/mol
  • Cl Chlorine × 111.87%
    35.45 × 1 = 35.450 g/mol
  • F Fluorine × 212.73%
    18.998 × 2 = 37.996 g/mol
  • N Nitrogen × 14.69%
    14.007 × 1 = 14.007 g/mol
Look up another formula

Compounds with the formula C10H11BrClF2N

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 4 of 4 compounds

Frequently asked questions

What is the molar mass of C10H11BrClF2N?

The molar mass of C10H11BrClF2N is 298.55 g/mol, calculated from standard atomic weights for 10 carbon atoms, 11 hydrogen atoms, 1 bromine atom, 1 chlorine atom, 2 fluorine atoms and 1 nitrogen atom. The monoisotopic mass is 296.9731 Da.

How many compounds have the formula C10H11BrClF2N?

CompoundList lists 4 compounds with the molecular formula C10H11BrClF2N, including 1-(4-Bromophenyl)-3,3-difluorocyclobutan-1-amine hydrochloride, (4-Bromo-2,5-difluorophenyl)(cyclopropyl)methanamine hydrochloride, 6-Bromo-3-(difluoromethyl)-1,2,3,4-tetrahydroisoquinoline hydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C10H11BrClF2N?

C10H11BrClF2N has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.