Molecular formula

C₁₀H₁₃BF₅KO₂

1 compound has this formula on CompoundList.

Molar mass: 310.11g/mol
Monoisotopic mass: 310.0566Da
Atoms: 32
Elements: 6

The formula C10H13BF5KO2 describes a molecule made of 10 carbon atoms, 13 hydrogen atoms, 1 boron atom, 5 fluorine atoms, 1 potassium atom and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

C Carbon × 1038.73%
12.011 × 10 = 120.110 g/mol
H Hydrogen × 134.23%
1.008 × 13 = 13.104 g/mol
B Boron × 13.49%
10.81 × 1 = 10.810 g/mol
F Fluorine × 530.63%
18.998 × 5 = 94.990 g/mol
K Potassium × 112.61%
39.098 × 1 = 39.098 g/mol
O Oxygen × 210.32%
15.999 × 2 = 31.998 g/mol

Look up another formula

Compounds with the formula C10H13BF5KO2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

$Potassium {2,2-difluoro-7,10-dioxadispiro[2.2.4^{6}.2^{3}]dodecan-1-yl}trifluoroboranuide chemical structure, C10H13BF5KO2, CAS 2416056-44-3$

Potassium {2,2-difluoro-7,10-dioxadispiro[2.2.4^{6}.2^{3}]dodecan-1-yl}trifluoroboranuide

CAS 2416056-44-3C₁₀H₁₃BF₅KO₂

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What is the molar mass of C10H13BF5KO2?

The molar mass of C10H13BF5KO2 is 310.11 g/mol, calculated from standard atomic weights for 10 carbon atoms, 13 hydrogen atoms, 1 boron atom, 5 fluorine atoms, 1 potassium atom and 2 oxygen atoms. The monoisotopic mass is 310.0566 Da.

How many compounds have the formula C10H13BF5KO2?

CompoundList lists 1 compound with the molecular formula C10H13BF5KO2, including Potassium {2,2-difluoro-7,10-dioxadispiro[2.2.4^{6}.2^{3}]dodecan-1-yl}trifluoroboranuide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.