C10H14ClNO4
36 compounds have this formula on CompoundList.
- Molar mass
- 247.67g/mol
- Monoisotopic mass
- 247.0611Da
- Atoms
- 30
- Elements
- 5
- Rings plus double bonds
- 4
The formula C10H14ClNO4 describes a molecule made of 10 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1048.50%12.011 × 10 = 120.110 g/mol
- H Hydrogen × 145.70%1.008 × 14 = 14.112 g/mol
- Cl Chlorine × 114.31%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 15.66%14.007 × 1 = 14.007 g/mol
- O Oxygen × 425.84%15.999 × 4 = 63.996 g/mol
Compounds with the formula C10H14ClNO4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 36 of 36 compounds
- 2-Amino-4-hydroxy-4-(3-hydroxyphenyl)butanoic acid hydrochloride1779441-65-4C10H14ClNO4
- 2-Chloro-N-[1-(hydroxymethyl)spiro[2-oxabicyclo[2.1.1]hexane-3,3'-oxetane]-4-yl]acetamide2490374-64-4C10H14ClNO4
- 5-Chloro-4-(dimethoxymethyl)-2,3-dimethoxypyridine1305324-79-1C10H14ClNO4
- 3-(2-Aminoethoxy)-4-methoxybenzoic acid hydrochloride2839156-18-0C10H14ClNO4
- 2,5-Dioxopyrrolidin-1-yl 6-chlorohexanoate761411-56-7C10H14ClNO4
- Methylcarbamic acid--2-(4-chlorophenoxy)ethan-1-ol (1/1)113137-66-9C10H14ClNO4
- (R)-2-Amino-3-(3-hydroxy-4-methoxyphenyl)propanoic acid hydrochloride2708342-46-3C10H14ClNO4
- (S)-2-Amino-2-(4-(2-hydroxyethoxy)phenyl)acetic acid hydrochloride2708340-97-8C10H14ClNO4
- (R)-2-Amino-2-(4-(2-hydroxyethoxy)phenyl)acetic acid hydrochloride2708344-34-5C10H14ClNO4
- 1-O-(1-Chloroethyl) 5-O-methyl 3,6-dihydro-2H-pyridine-1,5-dicarboxylate92600-27-6C10H14ClNO4
- (S)-2-Amino-2-(3,5-dimethoxyphenyl)acetic acid hydrochloride103889-82-3C10H14ClNO4
- (R)-2-Amino-2-(3,5-dimethoxyphenyl)acetic acid hydrochloride103889-80-1C10H14ClNO4
Frequently asked questions
What is the molar mass of C10H14ClNO4?
The molar mass of C10H14ClNO4 is 247.67 g/mol, calculated from standard atomic weights for 10 carbon atoms, 14 hydrogen atoms, 1 chlorine atom, 1 nitrogen atom and 4 oxygen atoms. The monoisotopic mass is 247.0611 Da.
How many compounds have the formula C10H14ClNO4?
CompoundList lists 36 compounds with the molecular formula C10H14ClNO4, including Melevodopa hydrochloride, 5-((Morpholin-4-yl)methyl)furan-2-carboxylic acid hydrochloride, 3-O-Methyldopa hydrochloride, DL-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C10H14ClNO4?
C10H14ClNO4 has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.