CompoundList
Molecular formula

C10H14IN3

12 compounds have this formula on CompoundList.

Molar mass
303.14g/mol
Monoisotopic mass
303.0232Da
Atoms
28
Elements
4
Rings plus double bonds
5

The formula C10H14IN3 describes a molecule made of 10 carbon atoms, 14 hydrogen atoms, 1 iodine atom and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1039.62%
    12.011 × 10 = 120.110 g/mol
  • H Hydrogen × 144.66%
    1.008 × 14 = 14.112 g/mol
  • I Iodine × 141.86%
    126.9 × 1 = 126.900 g/mol
  • N Nitrogen × 313.86%
    14.007 × 3 = 42.021 g/mol
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Compounds with the formula C10H14IN3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 12 of 12 compounds

Frequently asked questions

What is the molar mass of C10H14IN3?

The molar mass of C10H14IN3 is 303.14 g/mol, calculated from standard atomic weights for 10 carbon atoms, 14 hydrogen atoms, 1 iodine atom and 3 nitrogen atoms. The monoisotopic mass is 303.0232 Da.

How many compounds have the formula C10H14IN3?

CompoundList lists 12 compounds with the molecular formula C10H14IN3, including 1,2,3,4-Tetrahydroisoquinoline-2-carboximidamide hydroiodide, 3-Amino-1-methyl-1-phenyl-4,5-dihydro-1H-pyrazol-1-ium, iodide, 1-(6-Iodopyridin-2-yl)-4-methylpiperazine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C10H14IN3?

C10H14IN3 has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.