CompoundList
Molecular formula

C10H17N2O15P3

11 compounds have this formula on CompoundList.

Molar mass
498.17g/mol
Monoisotopic mass
497.9842Da
Atoms
47
Elements
5
Rings plus double bonds
5

The formula C10H17N2O15P3 describes a molecule made of 10 carbon atoms, 17 hydrogen atoms, 2 nitrogen atoms, 15 oxygen atoms and 3 phosphorus atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1024.11%
    12.011 × 10 = 120.110 g/mol
  • H Hydrogen × 173.44%
    1.008 × 17 = 17.136 g/mol
  • N Nitrogen × 25.62%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 1548.17%
    15.999 × 15 = 239.985 g/mol
  • P Phosphorus × 318.65%
    30.974 × 3 = 92.922 g/mol
Look up another formula

Compounds with the formula C10H17N2O15P3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 11 of 11 compounds

Frequently asked questions

What is the molar mass of C10H17N2O15P3?

The molar mass of C10H17N2O15P3 is 498.17 g/mol, calculated from standard atomic weights for 10 carbon atoms, 17 hydrogen atoms, 2 nitrogen atoms, 15 oxygen atoms and 3 phosphorus atoms. The monoisotopic mass is 497.9842 Da.

How many compounds have the formula C10H17N2O15P3?

CompoundList lists 11 compounds with the molecular formula C10H17N2O15P3, including 5-Methyluridine 5'-triphosphate, Hydroxymethyldeoxyuridine triphosphate, Arabinosylthymine 5'-triphosphate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C10H17N2O15P3?

C10H17N2O15P3 has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.