C10H18F6N2O4S2
1 compound has this formula on CompoundList.
- Molar mass
- 408.37g/mol
- Monoisotopic mass
- 408.0612Da
- Atoms
- 42
- Elements
- 6
- Rings plus double bonds
- 0
The formula C10H18F6N2O4S2 describes a molecule made of 10 carbon atoms, 18 hydrogen atoms, 6 fluorine atoms, 2 nitrogen atoms, 4 oxygen atoms and 2 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1029.41%12.011 × 10 = 120.110 g/mol
- H Hydrogen × 184.44%1.008 × 18 = 18.144 g/mol
- F Fluorine × 627.91%18.998 × 6 = 113.988 g/mol
- N Nitrogen × 26.86%14.007 × 2 = 28.014 g/mol
- O Oxygen × 415.67%15.999 × 4 = 63.996 g/mol
- S Sulfur × 215.70%32.06 × 2 = 64.120 g/mol
Compounds with the formula C10H18F6N2O4S2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C10H18F6N2O4S2?
The molar mass of C10H18F6N2O4S2 is 408.37 g/mol, calculated from standard atomic weights for 10 carbon atoms, 18 hydrogen atoms, 6 fluorine atoms, 2 nitrogen atoms, 4 oxygen atoms and 2 sulfur atoms. The monoisotopic mass is 408.0612 Da.
How many compounds have the formula C10H18F6N2O4S2?
CompoundList lists 1 compound with the molecular formula C10H18F6N2O4S2, including 1-Methyl-1-propylpyrrolidinium Bis(trifluoromethanesulfonyl)imide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C10H18F6N2O4S2?
C10H18F6N2O4S2 has a degree of unsaturation of 0. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.