CompoundList
Molecular formula

C10H6FN5

8 compounds have this formula on CompoundList.

Molar mass
215.19g/mol
Monoisotopic mass
215.0607Da
Atoms
22
Elements
4
Rings plus double bonds
10

The formula C10H6FN5 describes a molecule made of 10 carbon atoms, 6 hydrogen atoms, 1 fluorine atom and 5 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1055.82%
    12.011 × 10 = 120.110 g/mol
  • H Hydrogen × 62.81%
    1.008 × 6 = 6.048 g/mol
  • F Fluorine × 18.83%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 532.55%
    14.007 × 5 = 70.035 g/mol
Look up another formula

Compounds with the formula C10H6FN5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 8 of 8 compounds

Frequently asked questions

What is the molar mass of C10H6FN5?

The molar mass of C10H6FN5 is 215.19 g/mol, calculated from standard atomic weights for 10 carbon atoms, 6 hydrogen atoms, 1 fluorine atom and 5 nitrogen atoms. The monoisotopic mass is 215.0607 Da.

How many compounds have the formula C10H6FN5?

CompoundList lists 8 compounds with the molecular formula C10H6FN5, including 4-(3-Amino-1,2,4-triazin-6-yl)-2-fluorobenzonitrile, 1-(5-Fluoro-2-pyrimidinyl)-1H-imidazo[4,5-c]pyridine, 1-(6-Fluoro-2-pyridinyl)-1H-1,2,3-triazolo[4,5-c]pyridine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C10H6FN5?

C10H6FN5 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.