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Molecular formula

C10H7FN4OS

6 compounds have this formula on CompoundList.

Molar mass
250.25g/mol
Monoisotopic mass
250.0325Da
Atoms
24
Elements
6
Rings plus double bonds
9

The formula C10H7FN4OS describes a molecule made of 10 carbon atoms, 7 hydrogen atoms, 1 fluorine atom, 4 nitrogen atoms, 1 oxygen atom and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1048.00%
    12.011 × 10 = 120.110 g/mol
  • H Hydrogen × 72.82%
    1.008 × 7 = 7.056 g/mol
  • F Fluorine × 17.59%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 422.39%
    14.007 × 4 = 56.028 g/mol
  • O Oxygen × 16.39%
    15.999 × 1 = 15.999 g/mol
  • S Sulfur × 112.81%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C10H7FN4OS

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 6 of 6 compounds

N-[(Z)-(4-Fluorophenyl)methylideneamino]thiadiazole-4-carboxamide chemical structure, C10H7FN4OS, CAS 477872-08-5
N-[(Z)-(4-Fluorophenyl)methylideneamino]thiadiazole-4-carboxamide
CAS 477872-08-5C10H7FN4OS
6-[(4-Fluorophenoxy)methyl][1,2,4]triazolo[3,4-b][1,3,4]thiadiazole chemical structure, C10H7FN4OS, CAS 876886-30-5
6-[(4-Fluorophenoxy)methyl][1,2,4]triazolo[3,4-b][1,3,4]thiadiazole
CAS 876886-30-5C10H7FN4OS
N'-[(Z)-(4-Fluorophenyl)methylidene]-1,2,3-thiadiazole-4-carbohydrazide chemical structure, C10H7FN4OS
N'-[(Z)-(4-Fluorophenyl)methylidene]-1,2,3-thiadiazole-4-carbohydrazide
C10H7FN4OS
N-(Cyanomethyl)-5-fluoro-2-sulfanyl-1H-1,3-benzodiazole-7-carboxamide chemical structure, C10H7FN4OS, CAS 1808796-23-7
N-(Cyanomethyl)-5-fluoro-2-sulfanyl-1H-1,3-benzodiazole-7-carboxamide
CAS 1808796-23-7C10H7FN4OS
5-(Azidomethyl)-2-(4-fluorophenoxy)thiazole chemical structure, C10H7FN4OS, CAS 3029023-22-8
5-(Azidomethyl)-2-(4-fluorophenoxy)thiazole
CAS 3029023-22-8C10H7FN4OS
N-[(E)-(4-Fluorophenyl)methylideneamino]thiadiazole-4-carboxamide chemical structure, C10H7FN4OS
N-[(E)-(4-Fluorophenyl)methylideneamino]thiadiazole-4-carboxamide
C10H7FN4OS

Frequently asked questions

What is the molar mass of C10H7FN4OS?

The molar mass of C10H7FN4OS is 250.25 g/mol, calculated from standard atomic weights for 10 carbon atoms, 7 hydrogen atoms, 1 fluorine atom, 4 nitrogen atoms, 1 oxygen atom and 1 sulfur atom. The monoisotopic mass is 250.0325 Da.

How many compounds have the formula C10H7FN4OS?

CompoundList lists 6 compounds with the molecular formula C10H7FN4OS, including N-[(Z)-(4-Fluorophenyl)methylideneamino]thiadiazole-4-carboxamide, 6-[(4-Fluorophenoxy)methyl][1,2,4]triazolo[3,4-b][1,3,4]thiadiazole, N'-[(Z)-(4-Fluorophenyl)methylidene]-1,2,3-thiadiazole-4-carbohydrazide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C10H7FN4OS?

C10H7FN4OS has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.