CompoundList
Molecular formula

C10H8F4O4

9 compounds have this formula on CompoundList.

Molar mass
268.16g/mol
Monoisotopic mass
268.0359Da
Atoms
26
Elements
4
Rings plus double bonds
5

The formula C10H8F4O4 describes a molecule made of 10 carbon atoms, 8 hydrogen atoms, 4 fluorine atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1044.79%
    12.011 × 10 = 120.110 g/mol
  • H Hydrogen × 83.01%
    1.008 × 8 = 8.064 g/mol
  • F Fluorine × 428.34%
    18.998 × 4 = 75.992 g/mol
  • O Oxygen × 423.86%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C10H8F4O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 9 of 9 compounds

Frequently asked questions

What is the molar mass of C10H8F4O4?

The molar mass of C10H8F4O4 is 268.16 g/mol, calculated from standard atomic weights for 10 carbon atoms, 8 hydrogen atoms, 4 fluorine atoms and 4 oxygen atoms. The monoisotopic mass is 268.0359 Da.

How many compounds have the formula C10H8F4O4?

CompoundList lists 9 compounds with the molecular formula C10H8F4O4, including Methyl 2,4-bis(difluoromethoxy)benzoate, 3-Carbethoxy-2,6-bis(difluoromethyl)-4H-pyran-4-one, Benzoic acid, 2-hydroxy-4-(2,2,3,3-tetrafluoropropoxy)-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C10H8F4O4?

C10H8F4O4 has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.