C112H175N39O35S3
1 compound has this formula on CompoundList.
- Molar mass
- 2724.05g/mol
- Monoisotopic mass
- 2722.2275Da
- Atoms
- 364
- Elements
- 5
- Rings plus double bonds
- 45
The formula C112H175N39O35S3 describes a molecule made of 112 carbon atoms, 175 hydrogen atoms, 39 nitrogen atoms, 35 oxygen atoms and 3 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 11249.38%12.011 × 112 = 1345.232 g/mol
- H Hydrogen × 1756.48%1.008 × 175 = 176.400 g/mol
- N Nitrogen × 3920.05%14.007 × 39 = 546.273 g/mol
- O Oxygen × 3520.56%15.999 × 35 = 559.965 g/mol
- S Sulfur × 33.53%32.06 × 3 = 96.180 g/mol
Compounds with the formula C112H175N39O35S3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C112H175N39O35S3?
The molar mass of C112H175N39O35S3 is 2724.05 g/mol, calculated from standard atomic weights for 112 carbon atoms, 175 hydrogen atoms, 39 nitrogen atoms, 35 oxygen atoms and 3 sulfur atoms. The monoisotopic mass is 2722.2275 Da.
How many compounds have the formula C112H175N39O35S3?
CompoundList lists 1 compound with the molecular formula C112H175N39O35S3, including Anaritide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C112H175N39O35S3?
C112H175N39O35S3 has a degree of unsaturation of 45. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.