CompoundList
Molecular formula

C116H161N27O32S4

1 compound has this formula on CompoundList.

Molar mass
2573.96g/mol
Monoisotopic mass
2572.0684Da
Atoms
340
Elements
5
Rings plus double bonds
50

The formula C116H161N27O32S4 describes a molecule made of 116 carbon atoms, 161 hydrogen atoms, 27 nitrogen atoms, 32 oxygen atoms and 4 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 11654.13%
    12.011 × 116 = 1393.276 g/mol
  • H Hydrogen × 1616.30%
    1.008 × 161 = 162.288 g/mol
  • N Nitrogen × 2714.69%
    14.007 × 27 = 378.189 g/mol
  • O Oxygen × 3219.89%
    15.999 × 32 = 511.968 g/mol
  • S Sulfur × 44.98%
    32.06 × 4 = 128.240 g/mol
Look up another formula

Compounds with the formula C116H161N27O32S4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C116H161N27O32S4?

The molar mass of C116H161N27O32S4 is 2573.96 g/mol, calculated from standard atomic weights for 116 carbon atoms, 161 hydrogen atoms, 27 nitrogen atoms, 32 oxygen atoms and 4 sulfur atoms. The monoisotopic mass is 2572.0684 Da.

How many compounds have the formula C116H161N27O32S4?

CompoundList lists 1 compound with the molecular formula C116H161N27O32S4, including L-Cys(1)-L-Ser-L-Cys(2)-L-Asn-L-Ser-L-Trp-L-Leu-L-Asp-L-Lys-L-Glu-L-Cys(2)-L-Val-L-Tyr-L-Phe-L-Cys(1. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C116H161N27O32S4?

C116H161N27O32S4 has a degree of unsaturation of 50. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.