C11H15BClNO2
27 compounds have this formula on CompoundList.
- Molar mass
- 239.51g/mol
- Monoisotopic mass
- 242.1073Da
- Atoms
- 31
- Elements
- 6
The formula C11H15BClNO2 describes a molecule made of 11 carbon atoms, 15 hydrogen atoms, 1 boron atom, 1 chlorine atom, 1 nitrogen atom and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1155.16%12.011 × 11 = 132.121 g/mol
- H Hydrogen × 156.31%1.008 × 15 = 15.120 g/mol
- B Boron × 14.51%10.81 × 1 = 10.810 g/mol
- Cl Chlorine × 114.80%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 15.85%14.007 × 1 = 14.007 g/mol
- O Oxygen × 213.36%15.999 × 2 = 31.998 g/mol
Compounds with the formula C11H15BClNO2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 27 of 27 compounds
Frequently asked questions
What is the molar mass of C11H15BClNO2?
The molar mass of C11H15BClNO2 is 239.51 g/mol, calculated from standard atomic weights for 11 carbon atoms, 15 hydrogen atoms, 1 boron atom, 1 chlorine atom, 1 nitrogen atom and 2 oxygen atoms. The monoisotopic mass is 242.1073 Da.
How many compounds have the formula C11H15BClNO2?
CompoundList lists 27 compounds with the molecular formula C11H15BClNO2, including 2-Chloropyridine-4-boronic acid, pinacol ester, 2-Chloro-5-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)pyridine, 2-Chloropyridine-3-boronic acid pinacol ester. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.