Molecular formula

C₁₁H₁₇N₅OS

21 compounds have this formula on CompoundList.

Molar mass: 267.35g/mol
Monoisotopic mass: 267.1154Da
Atoms: 35
Elements: 5
Rings plus double bonds: 6

The formula C11H17N5OS describes a molecule made of 11 carbon atoms, 17 hydrogen atoms, 5 nitrogen atoms, 1 oxygen atom and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

C Carbon × 1149.42%
12.011 × 11 = 132.121 g/mol
H Hydrogen × 176.41%
1.008 × 17 = 17.136 g/mol
N Nitrogen × 526.20%
14.007 × 5 = 70.035 g/mol
O Oxygen × 15.98%
15.999 × 1 = 15.999 g/mol
S Sulfur × 111.99%
32.06 × 1 = 32.060 g/mol

Look up another formula

Compounds with the formula C11H17N5OS

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 21 of 21 compounds

Ethyl N-cyano-N'-(2-((5-methyl-1H-imidazol-4-yl)methylsulfanyl)ethyl)carbamimidate

CAS 75850-09-8C₁₁H₁₇N₅OS

N-(2-Cyano-3-methylbutan-2-yl)-2-[(4-methyl-1,2,4-triazol-3-yl)sulfanyl]acetamide

CAS 872022-70-3C₁₁H₁₇N₅OS

Mtp 1403

CAS 87466-13-5C₁₁H₁₇N₅OS

4-(3-Methoxypropyl)-5-((3-methyl-1H-pyrazol-1-yl)methyl)-4H-1,2,4-triazole-3-thiol

CAS 1002032-55-4C₁₁H₁₇N₅OS

Acetic acid, ((6-(dimethylamino)-4-pyrimidinyl)thio)-, (1-methylethylidene)hydrazide

CAS 95546-92-2C₁₁H₁₇N₅OS

Acetic acid, ((6-(1-piperidinyl)-4-pyrimidinyl)thio)-, hydrazide

CAS 95546-91-1C₁₁H₁₇N₅OS

Glycine, N,N-dimethyl-, ((2,3-dihydro-6-methylimidazo(2,1-b)thiazol-5-yl)methylene)hydrazide

CAS 102410-37-7C₁₁H₁₇N₅OS

5-(3-Ethoxy-1-ethyl-1H-pyrazol-4-yl)-4-ethyl-4H-1,2,4-triazole-3-thiol

CAS 1171329-39-7C₁₁H₁₇N₅OS

3-(Isopropylthio)-5-(3-methoxy-1-methyl-1H-pyrazol-4-yl)-4-methyl-4H-1,2,4-triazole

CAS 1013774-45-2C₁₁H₁₇N₅OS

1-Cyclopropyl-3-[3-(3-methylpyrazol-1-yl)propanoylamino]thiourea

CAS 1005696-59-2C₁₁H₁₇N₅OS

3-(3-Methoxy-1-methyl-1H-pyrazol-4-yl)-4-methyl-5-(propylthio)-4H-1,2,4-triazole

CAS 1014096-13-9C₁₁H₁₇N₅OS

4-Ethyl-3-(ethylsulfanyl)-5-(3-methoxy-1-methyl-1H-pyrazol-4-yl)-4H-1,2,4-triazole

CAS 1014093-37-8C₁₁H₁₇N₅OS

4-(5-Cyclohexyl-1,3,4-thiadiazol-2-yl)-2-methyl-1,2,4-triazolidin-3-one

CAS 57773-98-5C₁₁H₁₇N₅OS

N-(1-Cyano-1,2-dimethylpropyl)-2-(4H-1,2,4-triazol-3-ylsulfanyl)propanamide

CAS 1197929-39-7C₁₁H₁₇N₅OS

1-(5-(4-Aminopiperidin-1-yl)-1,3,4-thiadiazol-2-yl)pyrrolidin-2-one

CAS 2098080-15-8C₁₁H₁₇N₅OS

5-(Azidomethyl)-N-[3-(dimethylamino)propyl]thiophene-2-carboxamide

CAS 2322032-71-1C₁₁H₁₇N₅OS

3-[4-(1,2,5-Thiadiazol-3-yl)piperazin-1-yl]piperidin-2-one

CAS 2548976-00-5C₁₁H₁₇N₅OS

N-[1-(Azetidin-3-yl)-1H-pyrazol-5-yl]-2-carbamothioylbutanamide

CAS 2137852-40-3C₁₁H₁₇N₅OS

N-[1-(Azetidin-3-yl)-1H-pyrazol-5-yl]thiomorpholine-2-carboxamide

CAS 2138285-04-6C₁₁H₁₇N₅OS

N-[1-(Azetidin-3-yl)-1H-pyrazol-5-yl]-2-carbamothioyl-2,2-dimethylacetamide

CAS 2138015-54-8C₁₁H₁₇N₅OS

N-[1-(Azetidin-3-yl)-1H-pyrazol-5-yl]thiomorpholine-3-carboxamide

CAS 2137488-40-3C₁₁H₁₇N₅OS

Frequently asked questions

Still have a question?

The help centre explains buying, quotes and supplier badges step by step, or you can write to our team.

Help centre Contact us

What is the molar mass of C11H17N5OS?

The molar mass of C11H17N5OS is 267.35 g/mol, calculated from standard atomic weights for 11 carbon atoms, 17 hydrogen atoms, 5 nitrogen atoms, 1 oxygen atom and 1 sulfur atom. The monoisotopic mass is 267.1154 Da.

How many compounds have the formula C11H17N5OS?

CompoundList lists 21 compounds with the molecular formula C11H17N5OS, including Ethyl N-cyano-N'-(2-((5-methyl-1H-imidazol-4-yl)methylsulfanyl)ethyl)carbamimidate, N-(2-Cyano-3-methylbutan-2-yl)-2-[(4-methyl-1,2,4-triazol-3-yl)sulfanyl]acetamide, Mtp 1403. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C11H17N5OS?

C11H17N5OS has a degree of unsaturation of 6. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.