C11H23N3Zr
1 compound has this formula on CompoundList.
- Molar mass
- 288.55g/mol
- Monoisotopic mass
- 287.0939Da
- Atoms
- 38
- Elements
- 4
The formula C11H23N3Zr describes a molecule made of 11 carbon atoms, 23 hydrogen atoms, 3 nitrogen atoms and 1 zirconium atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1145.79%12.011 × 11 = 132.121 g/mol
- H Hydrogen × 238.03%1.008 × 23 = 23.184 g/mol
- N Nitrogen × 314.56%14.007 × 3 = 42.021 g/mol
- Zr Zirconium × 131.61%91.224 × 1 = 91.224 g/mol
Compounds with the formula C11H23N3Zr
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C11H23N3Zr?
The molar mass of C11H23N3Zr is 288.55 g/mol, calculated from standard atomic weights for 11 carbon atoms, 23 hydrogen atoms, 3 nitrogen atoms and 1 zirconium atom. The monoisotopic mass is 287.0939 Da.
How many compounds have the formula C11H23N3Zr?
CompoundList lists 1 compound with the molecular formula C11H23N3Zr, including Zirconium, (eta5-2,4-cyclopentadien-1-yl)tris(N-methylmethanaminato)-. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.