CompoundList
Molecular formula

C11H7BF9N3

1 compound has this formula on CompoundList.

Molar mass
362.99g/mol
Monoisotopic mass
363.0589Da
Atoms
31
Elements
5

The formula C11H7BF9N3 describes a molecule made of 11 carbon atoms, 7 hydrogen atoms, 1 boron atom, 9 fluorine atoms and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1136.40%
    12.011 × 11 = 132.121 g/mol
  • H Hydrogen × 71.94%
    1.008 × 7 = 7.056 g/mol
  • B Boron × 12.98%
    10.81 × 1 = 10.810 g/mol
  • F Fluorine × 947.10%
    18.998 × 9 = 170.982 g/mol
  • N Nitrogen × 311.58%
    14.007 × 3 = 42.021 g/mol
Look up another formula

Compounds with the formula C11H7BF9N3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C11H7BF9N3?

The molar mass of C11H7BF9N3 is 362.99 g/mol, calculated from standard atomic weights for 11 carbon atoms, 7 hydrogen atoms, 1 boron atom, 9 fluorine atoms and 3 nitrogen atoms. The monoisotopic mass is 363.0589 Da.

How many compounds have the formula C11H7BF9N3?

CompoundList lists 1 compound with the molecular formula C11H7BF9N3, including 6,7-Dihydro-2-pentafluorophenyl-5H-pyrrolo[2,1-c]-1,2,4-triazolium tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.