C11H8N4S3
1 compound has this formula on CompoundList.
- Molar mass
- 292.39g/mol
- Monoisotopic mass
- 291.9911Da
- Atoms
- 26
- Elements
- 4
- Rings plus double bonds
- 10
The formula C11H8N4S3 describes a molecule made of 11 carbon atoms, 8 hydrogen atoms, 4 nitrogen atoms and 3 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1145.19%12.011 × 11 = 132.121 g/mol
- H Hydrogen × 82.76%1.008 × 8 = 8.064 g/mol
- N Nitrogen × 419.16%14.007 × 4 = 56.028 g/mol
- S Sulfur × 332.89%32.06 × 3 = 96.180 g/mol
Compounds with the formula C11H8N4S3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
![5-(2-Thienyl)-4-{[(E)-2-thienylmethylidene]amino}-4H-1,2,4-triazole-3-thiol chemical structure, C11H8N4S3, CAS 477863-25-5](/s/BBSKPRBMKRPTOV-KPKJPENVSA-N.svg)
Frequently asked questions
What is the molar mass of C11H8N4S3?
The molar mass of C11H8N4S3 is 292.39 g/mol, calculated from standard atomic weights for 11 carbon atoms, 8 hydrogen atoms, 4 nitrogen atoms and 3 sulfur atoms. The monoisotopic mass is 291.9911 Da.
How many compounds have the formula C11H8N4S3?
CompoundList lists 1 compound with the molecular formula C11H8N4S3, including 5-(2-Thienyl)-4-{[(E)-2-thienylmethylidene]amino}-4H-1,2,4-triazole-3-thiol. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C11H8N4S3?
C11H8N4S3 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.