CompoundList
Molecular formula

C124H203N33O38

1 compound has this formula on CompoundList.

Molar mass
2764.18g/mol
Monoisotopic mass
2762.4967Da
Atoms
398
Elements
4
Rings plus double bonds
40

The formula C124H203N33O38 describes a molecule made of 124 carbon atoms, 203 hydrogen atoms, 33 nitrogen atoms and 38 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 12453.88%
    12.011 × 124 = 1489.364 g/mol
  • H Hydrogen × 2037.40%
    1.008 × 203 = 204.624 g/mol
  • N Nitrogen × 3316.72%
    14.007 × 33 = 462.231 g/mol
  • O Oxygen × 3821.99%
    15.999 × 38 = 607.962 g/mol
Look up another formula

Compounds with the formula C124H203N33O38

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

Frequently asked questions

What is the molar mass of C124H203N33O38?

The molar mass of C124H203N33O38 is 2764.18 g/mol, calculated from standard atomic weights for 124 carbon atoms, 203 hydrogen atoms, 33 nitrogen atoms and 38 oxygen atoms. The monoisotopic mass is 2762.4967 Da.

How many compounds have the formula C124H203N33O38?

CompoundList lists 1 compound with the molecular formula C124H203N33O38, including Tecemotide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C124H203N33O38?

C124H203N33O38 has a degree of unsaturation of 40. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.