Molecular formula

C₁₂H₁₄BrF₂NO₂

22 compounds have this formula on CompoundList.

Molar mass: 322.15g/mol
Monoisotopic mass: 321.0176Da
Atoms: 32
Elements: 6
Rings plus double bonds: 5

The formula C12H14BrF2NO2 describes a molecule made of 12 carbon atoms, 14 hydrogen atoms, 1 bromine atom, 2 fluorine atoms, 1 nitrogen atom and 2 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

C Carbon × 1244.74%
12.011 × 12 = 144.132 g/mol
H Hydrogen × 144.38%
1.008 × 14 = 14.112 g/mol
Br Bromine × 124.80%
79.904 × 1 = 79.904 g/mol
F Fluorine × 211.79%
18.998 × 2 = 37.996 g/mol
N Nitrogen × 14.35%
14.007 × 1 = 14.007 g/mol
O Oxygen × 29.93%
15.999 × 2 = 31.998 g/mol

Look up another formula

Compounds with the formula C12H14BrF2NO2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 22 of 22 compounds

Ethyl 5,6-difluoro-1,2,3,4-tetrahydroisoquinoline-1-carboxylate hydrobromide

CAS 2241139-26-2C₁₂H₁₄BrF₂NO₂

tert-Butyl (4-bromo-2,6-difluorobenzyl)carbamate

CAS 1402673-66-8C₁₂H₁₄BrF₂NO₂

tert-Butyl 2-bromo-3,4-difluorobenzylcarbamate

CAS 2231675-56-0C₁₂H₁₄BrF₂NO₂

tert-Butyl N-[(4-bromo-2,3-difluorophenyl)methyl]carbamate

CAS 2222960-71-4C₁₂H₁₄BrF₂NO₂

tert-Butyl N-[(4-bromo-2,5-difluorophenyl)methyl]carbamate

CAS 2680678-38-8C₁₂H₁₄BrF₂NO₂

Ethyl 2-[5-bromo-2-(dimethylamino)phenyl]-2,2-difluoroacetate

CAS 1286792-92-4C₁₂H₁₄BrF₂NO₂

tert-Butyl 5-bromo-2,4-difluorobenzylcarbamate

CAS 2567137-90-8C₁₂H₁₄BrF₂NO₂

tert-Butyl (4-bromo-3,5-difluorobenzyl)carbamate

CAS 1807849-30-4C₁₂H₁₄BrF₂NO₂

4-Bromo-3-(difluoromethoxy)-N,N-diethylbenzamide

CAS 2989216-23-9C₁₂H₁₄BrF₂NO₂

Ethyl 6-(bromodifluoromethyl)-4-ethyl-2-methylpyridine-3-carboxylate

CAS 2137874-31-6C₁₂H₁₄BrF₂NO₂

6-(Bromodifluoromethyl)-4,5-dimethyl-2-(propan-2-yl)pyridine-3-carboxylic acid

CAS 2138340-26-6C₁₂H₁₄BrF₂NO₂

Ethyl 6-(bromodifluoromethyl)-2-ethyl-4-methylpyridine-3-carboxylate

CAS 2138340-89-1C₁₂H₁₄BrF₂NO₂

Ethyl 6-(bromodifluoromethyl)-2,4,5-trimethylpyridine-3-carboxylate

CAS 2137577-59-2C₁₂H₁₄BrF₂NO₂

6-(Bromodifluoromethyl)-4-ethyl-2-(propan-2-yl)pyridine-3-carboxylic acid

CAS 2137874-91-8C₁₂H₁₄BrF₂NO₂

tert-Butyl N-[(3-bromo-2,6-difluorophenyl)methyl]carbamate

CAS 2680860-43-7C₁₂H₁₄BrF₂NO₂

tert-Butyl N-[4-bromo-3-(difluoromethyl)phenyl]carbamate

CAS 2680700-18-7C₁₂H₁₄BrF₂NO₂

tert-Butyl N-[(2-bromo-4,5-difluorophenyl)methyl]carbamate

CAS 2270183-73-6C₁₂H₁₄BrF₂NO₂

tert-Butyl N-[5-bromo-2-(difluoromethyl)phenyl]carbamate

CAS 2680693-78-9C₁₂H₁₄BrF₂NO₂

3-Bromo-5-(difluoromethoxy)-N,N-diethylbenzamide

CAS 3078376-59-4C₁₂H₁₄BrF₂NO₂

6-Bromo-N-(2,2-difluoroethyl)-3-ethoxy-2-methylbenzamide

CAS 3078455-38-3C₁₂H₁₄BrF₂NO₂

N-(3-Bromo-4-(difluoromethoxy)benzyl)tetrahydrofuran-3-amine

CAS 3078555-39-9C₁₂H₁₄BrF₂NO₂

4-(3-Bromo-4-(difluoromethoxy)benzyl)morpholine

CAS 3078574-85-0C₁₂H₁₄BrF₂NO₂

Frequently asked questions

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What is the molar mass of C12H14BrF2NO2?

The molar mass of C12H14BrF2NO2 is 322.15 g/mol, calculated from standard atomic weights for 12 carbon atoms, 14 hydrogen atoms, 1 bromine atom, 2 fluorine atoms, 1 nitrogen atom and 2 oxygen atoms. The monoisotopic mass is 321.0176 Da.

How many compounds have the formula C12H14BrF2NO2?

CompoundList lists 22 compounds with the molecular formula C12H14BrF2NO2, including Ethyl 5,6-difluoro-1,2,3,4-tetrahydroisoquinoline-1-carboxylate hydrobromide, tert-Butyl (4-bromo-2,6-difluorobenzyl)carbamate, tert-Butyl 2-bromo-3,4-difluorobenzylcarbamate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C12H14BrF2NO2?

C12H14BrF2NO2 has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.