CompoundList
Molecular formula

C12H17BN2O5

6 compounds have this formula on CompoundList.

Molar mass
280.09g/mol
Monoisotopic mass
280.1231Da
Atoms
37
Elements
5

The formula C12H17BN2O5 describes a molecule made of 12 carbon atoms, 17 hydrogen atoms, 1 boron atom, 2 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1251.46%
    12.011 × 12 = 144.132 g/mol
  • H Hydrogen × 176.12%
    1.008 × 17 = 17.136 g/mol
  • B Boron × 13.86%
    10.81 × 1 = 10.810 g/mol
  • N Nitrogen × 210.00%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 528.56%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C12H17BN2O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 6 of 6 compounds

Frequently asked questions

What is the molar mass of C12H17BN2O5?

The molar mass of C12H17BN2O5 is 280.09 g/mol, calculated from standard atomic weights for 12 carbon atoms, 17 hydrogen atoms, 1 boron atom, 2 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 280.1231 Da.

How many compounds have the formula C12H17BN2O5?

CompoundList lists 6 compounds with the molecular formula C12H17BN2O5, including 2-Methoxy-5-nitro-3-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)pyridine, 2-Methoxy-3-nitro-5-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)pyridine, 1-Methyl-3-nitro-5-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)pyridin-2(1H)-one. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.