Molecular formula

C₁₂H₂₁F₃N₂O₅

2 compounds have this formula on CompoundList.

Molar mass: 330.30g/mol
Monoisotopic mass: 330.1403Da
Atoms: 43
Elements: 5
Rings plus double bonds: 2

The formula C12H21F3N2O5 describes a molecule made of 12 carbon atoms, 21 hydrogen atoms, 3 fluorine atoms, 2 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

C Carbon × 1243.64%
12.011 × 12 = 144.132 g/mol
H Hydrogen × 216.41%
1.008 × 21 = 21.168 g/mol
F Fluorine × 317.26%
18.998 × 3 = 56.994 g/mol
N Nitrogen × 28.48%
14.007 × 2 = 28.014 g/mol
O Oxygen × 524.22%
15.999 × 5 = 79.995 g/mol

Look up another formula

Compounds with the formula C12H21F3N2O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

tert-Butyl N-[3-(hydroxymethyl)azetidin-3-yl]-N-methylcarbamate, trifluoroacetic acid

CAS 2923844-97-5C₁₂H₂₁F₃N₂O₅

N-{2-[2-(2-Aminoethoxy)ethoxy]ethyl}-2-methylprop-2-enamide, trifluoroacetic acid

CAS 2870710-26-0C₁₂H₂₁F₃N₂O₅

Frequently asked questions

Still have a question?

The help centre explains buying, quotes and supplier badges step by step, or you can write to our team.

Help centre Contact us

What is the molar mass of C12H21F3N2O5?

The molar mass of C12H21F3N2O5 is 330.30 g/mol, calculated from standard atomic weights for 12 carbon atoms, 21 hydrogen atoms, 3 fluorine atoms, 2 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 330.1403 Da.

How many compounds have the formula C12H21F3N2O5?

CompoundList lists 2 compounds with the molecular formula C12H21F3N2O5, including tert-Butyl N-[3-(hydroxymethyl)azetidin-3-yl]-N-methylcarbamate, trifluoroacetic acid, N-{2-[2-(2-Aminoethoxy)ethoxy]ethyl}-2-methylprop-2-enamide, trifluoroacetic acid. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C12H21F3N2O5?

C12H21F3N2O5 has a degree of unsaturation of 2. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.