C12H50Cl2N14O12Pt3
1 compound has this formula on CompoundList.
- Molar mass
- 1238.76g/mol
- Monoisotopic mass
- 1237.2053Da
- Atoms
- 93
- Elements
- 6
The formula C12H50Cl2N14O12Pt3 describes a molecule made of 12 carbon atoms, 50 hydrogen atoms, 2 chlorine atoms, 14 nitrogen atoms, 12 oxygen atoms and 3 platinum atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1211.64%12.011 × 12 = 144.132 g/mol
- H Hydrogen × 504.07%1.008 × 50 = 50.400 g/mol
- Cl Chlorine × 25.72%35.45 × 2 = 70.900 g/mol
- N Nitrogen × 1415.83%14.007 × 14 = 196.098 g/mol
- O Oxygen × 1215.50%15.999 × 12 = 191.988 g/mol
- Pt Platinum × 347.24%195.08 × 3 = 585.240 g/mol
Compounds with the formula C12H50Cl2N14O12Pt3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C12H50Cl2N14O12Pt3?
The molar mass of C12H50Cl2N14O12Pt3 is 1238.76 g/mol, calculated from standard atomic weights for 12 carbon atoms, 50 hydrogen atoms, 2 chlorine atoms, 14 nitrogen atoms, 12 oxygen atoms and 3 platinum atoms. The monoisotopic mass is 1237.2053 Da.
How many compounds have the formula C12H50Cl2N14O12Pt3?
CompoundList lists 1 compound with the molecular formula C12H50Cl2N14O12Pt3, including Triplatin tetranitrate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.