C130H184N38O31S2
1 compound has this formula on CompoundList.
- Molar mass
- 2839.26g/mol
- Monoisotopic mass
- 2837.3431Da
- Atoms
- 385
- Elements
- 5
- Rings plus double bonds
- 58
The formula C130H184N38O31S2 describes a molecule made of 130 carbon atoms, 184 hydrogen atoms, 38 nitrogen atoms, 31 oxygen atoms and 2 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 13054.99%12.011 × 130 = 1561.430 g/mol
- H Hydrogen × 1846.53%1.008 × 184 = 185.472 g/mol
- N Nitrogen × 3818.75%14.007 × 38 = 532.266 g/mol
- O Oxygen × 3117.47%15.999 × 31 = 495.969 g/mol
- S Sulfur × 22.26%32.06 × 2 = 64.120 g/mol
Compounds with the formula C130H184N38O31S2
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C130H184N38O31S2?
The molar mass of C130H184N38O31S2 is 2839.26 g/mol, calculated from standard atomic weights for 130 carbon atoms, 184 hydrogen atoms, 38 nitrogen atoms, 31 oxygen atoms and 2 sulfur atoms. The monoisotopic mass is 2837.3431 Da.
How many compounds have the formula C130H184N38O31S2?
CompoundList lists 1 compound with the molecular formula C130H184N38O31S2, including Bam 22P. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C130H184N38O31S2?
C130H184N38O31S2 has a degree of unsaturation of 58. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.