C13H11BrClN3S
2 compounds have this formula on CompoundList.
- Molar mass
- 356.67g/mol
- Monoisotopic mass
- 354.9546Da
- Atoms
- 30
- Elements
- 6
- Rings plus double bonds
- 9
The formula C13H11BrClN3S describes a molecule made of 13 carbon atoms, 11 hydrogen atoms, 1 bromine atom, 1 chlorine atom, 3 nitrogen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1343.78%12.011 × 13 = 156.143 g/mol
- H Hydrogen × 113.11%1.008 × 11 = 11.088 g/mol
- Br Bromine × 122.40%79.904 × 1 = 79.904 g/mol
- Cl Chlorine × 19.94%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 311.78%14.007 × 3 = 42.021 g/mol
- S Sulfur × 18.99%32.06 × 1 = 32.060 g/mol
Compounds with the formula C13H11BrClN3S
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 2 of 2 compounds
Frequently asked questions
What is the molar mass of C13H11BrClN3S?
The molar mass of C13H11BrClN3S is 356.67 g/mol, calculated from standard atomic weights for 13 carbon atoms, 11 hydrogen atoms, 1 bromine atom, 1 chlorine atom, 3 nitrogen atoms and 1 sulfur atom. The monoisotopic mass is 354.9546 Da.
How many compounds have the formula C13H11BrClN3S?
CompoundList lists 2 compounds with the molecular formula C13H11BrClN3S, including 1-(4-Bromo-2-chlorophenyl)-3-(3-methyl-2-pyridinyl)thiourea, 1-(4-Bromo-2-chlorophenyl)-3-(pyridin-3-ylmethyl)thiourea. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C13H11BrClN3S?
C13H11BrClN3S has a degree of unsaturation of 9. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.