CompoundList
Molecular formula

C13H13N5O5

14 compounds have this formula on CompoundList.

Molar mass
319.28g/mol
Monoisotopic mass
319.0917Da
Atoms
36
Elements
4
Rings plus double bonds
10

The formula C13H13N5O5 describes a molecule made of 13 carbon atoms, 13 hydrogen atoms, 5 nitrogen atoms and 5 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1348.91%
    12.011 × 13 = 156.143 g/mol
  • H Hydrogen × 134.10%
    1.008 × 13 = 13.104 g/mol
  • N Nitrogen × 521.94%
    14.007 × 5 = 70.035 g/mol
  • O Oxygen × 525.06%
    15.999 × 5 = 79.995 g/mol
Look up another formula

Compounds with the formula C13H13N5O5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 14 of 14 compounds

Frequently asked questions

What is the molar mass of C13H13N5O5?

The molar mass of C13H13N5O5 is 319.28 g/mol, calculated from standard atomic weights for 13 carbon atoms, 13 hydrogen atoms, 5 nitrogen atoms and 5 oxygen atoms. The monoisotopic mass is 319.0917 Da.

How many compounds have the formula C13H13N5O5?

CompoundList lists 14 compounds with the molecular formula C13H13N5O5, including N-(3-Imidazol-1-ylpropyl)-3,5-dinitrobenzamide, N'-[(E)-(2,4-Dihydroxyphenyl)methylidene]-2-(5-methyl-3-nitro-1H-pyrazol-1-yl)acetohydrazide, 4-[5-(3,4,5-Trimethoxyphenyl)-1,2,4-oxadiazol-3-yl]-1,2,5-oxadiazol-3-amine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C13H13N5O5?

C13H13N5O5 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.