Molecular formula

C₁₃H₂₅B₂FO₄

1 compound has this formula on CompoundList.

Molar mass: 285.96g/mol
Monoisotopic mass: 286.1923Da
Atoms: 45
Elements: 5

The formula C13H25B2FO4 describes a molecule made of 13 carbon atoms, 25 hydrogen atoms, 2 boron atoms, 1 fluorine atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

C Carbon × 1354.60%
12.011 × 13 = 156.143 g/mol
H Hydrogen × 258.81%
1.008 × 25 = 25.200 g/mol
B Boron × 27.56%
10.81 × 2 = 21.620 g/mol
F Fluorine × 16.64%
18.998 × 1 = 18.998 g/mol
O Oxygen × 422.38%
15.999 × 4 = 63.996 g/mol

Look up another formula

Compounds with the formula C13H25B2FO4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 1 of 1 compounds

2-(Fluoro(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)methyl)-4,4,5,5-tetramethyl-1,3,2-dioxaborolane

CAS 2867598-03-4C₁₃H₂₅B₂FO₄

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What is the molar mass of C13H25B2FO4?

The molar mass of C13H25B2FO4 is 285.96 g/mol, calculated from standard atomic weights for 13 carbon atoms, 25 hydrogen atoms, 2 boron atoms, 1 fluorine atom and 4 oxygen atoms. The monoisotopic mass is 286.1923 Da.

How many compounds have the formula C13H25B2FO4?

CompoundList lists 1 compound with the molecular formula C13H25B2FO4, including 2-(Fluoro(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)methyl)-4,4,5,5-tetramethyl-1,3,2-dioxaborolane. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.