C13H2F10O
1 compound has this formula on CompoundList.
- Molar mass
- 364.14g/mol
- Monoisotopic mass
- 363.9946Da
- Atoms
- 26
- Elements
- 4
- Rings plus double bonds
- 8
The formula C13H2F10O describes a molecule made of 13 carbon atoms, 2 hydrogen atoms, 10 fluorine atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1342.88%12.011 × 13 = 156.143 g/mol
- H Hydrogen × 20.55%1.008 × 2 = 2.016 g/mol
- F Fluorine × 1052.17%18.998 × 10 = 189.980 g/mol
- O Oxygen × 14.39%15.999 × 1 = 15.999 g/mol
Compounds with the formula C13H2F10O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C13H2F10O?
The molar mass of C13H2F10O is 364.14 g/mol, calculated from standard atomic weights for 13 carbon atoms, 2 hydrogen atoms, 10 fluorine atoms and 1 oxygen atom. The monoisotopic mass is 363.9946 Da.
How many compounds have the formula C13H2F10O?
CompoundList lists 1 compound with the molecular formula C13H2F10O, including Bis(pentafluorophenyl)methanol. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C13H2F10O?
C13H2F10O has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.