CompoundList
Molecular formula

C13H7BrO4

3 compounds have this formula on CompoundList.

Molar mass
307.10g/mol
Monoisotopic mass
305.9528Da
Atoms
25
Elements
4
Rings plus double bonds
10

The formula C13H7BrO4 describes a molecule made of 13 carbon atoms, 7 hydrogen atoms, 1 bromine atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1350.84%
    12.011 × 13 = 156.143 g/mol
  • H Hydrogen × 72.30%
    1.008 × 7 = 7.056 g/mol
  • Br Bromine × 126.02%
    79.904 × 1 = 79.904 g/mol
  • O Oxygen × 420.84%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C13H7BrO4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Frequently asked questions

What is the molar mass of C13H7BrO4?

The molar mass of C13H7BrO4 is 307.10 g/mol, calculated from standard atomic weights for 13 carbon atoms, 7 hydrogen atoms, 1 bromine atom and 4 oxygen atoms. The monoisotopic mass is 305.9528 Da.

How many compounds have the formula C13H7BrO4?

CompoundList lists 3 compounds with the molecular formula C13H7BrO4, including 7-Bromo-1,3-dihydroxy-9H-xanthen-9-one, 3-(5-Bromofuran-2-yl)-2-hydroxy-4H-chromen-4-one, 3-Bromo-4-methyl-2H,5H-pyrano[3,2-c][1]benzopyran-2,5-dione. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C13H7BrO4?

C13H7BrO4 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.