C13H9FN4
13 compounds have this formula on CompoundList.
- Molar mass
- 240.24g/mol
- Monoisotopic mass
- 240.0811Da
- Atoms
- 27
- Elements
- 4
- Rings plus double bonds
- 11
The formula C13H9FN4 describes a molecule made of 13 carbon atoms, 9 hydrogen atoms, 1 fluorine atom and 4 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1364.99%12.011 × 13 = 156.143 g/mol
- H Hydrogen × 93.78%1.008 × 9 = 9.072 g/mol
- F Fluorine × 17.91%18.998 × 1 = 18.998 g/mol
- N Nitrogen × 423.32%14.007 × 4 = 56.028 g/mol
Compounds with the formula C13H9FN4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 13 of 13 compounds
Frequently asked questions
What is the molar mass of C13H9FN4?
The molar mass of C13H9FN4 is 240.24 g/mol, calculated from standard atomic weights for 13 carbon atoms, 9 hydrogen atoms, 1 fluorine atom and 4 nitrogen atoms. The monoisotopic mass is 240.0811 Da.
How many compounds have the formula C13H9FN4?
CompoundList lists 13 compounds with the molecular formula C13H9FN4, including 2-(4-Fluorophenyl)-5-phenyl-2H-tetrazole, 7-[(E)-2-(4-Fluorophenyl)ethenyl]-[1,2,4]triazolo[1,5-a]pyrimidine, 2-(1-(2-Fluorophenyl)-1H-pyrazol-5-yl)pyrimidine. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C13H9FN4?
C13H9FN4 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.