C143H244N50O42S4
1 compound has this formula on CompoundList.
- Molar mass
- 3464.07g/mol
- Monoisotopic mass
- 3461.7377Da
- Atoms
- 483
- Elements
- 5
- Rings plus double bonds
- 47
The formula C143H244N50O42S4 describes a molecule made of 143 carbon atoms, 244 hydrogen atoms, 50 nitrogen atoms, 42 oxygen atoms and 4 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 14349.58%12.011 × 143 = 1717.573 g/mol
- H Hydrogen × 2447.10%1.008 × 244 = 245.952 g/mol
- N Nitrogen × 5020.22%14.007 × 50 = 700.350 g/mol
- O Oxygen × 4219.40%15.999 × 42 = 671.958 g/mol
- S Sulfur × 43.70%32.06 × 4 = 128.240 g/mol
Compounds with the formula C143H244N50O42S4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C143H244N50O42S4?
The molar mass of C143H244N50O42S4 is 3464.07 g/mol, calculated from standard atomic weights for 143 carbon atoms, 244 hydrogen atoms, 50 nitrogen atoms, 42 oxygen atoms and 4 sulfur atoms. The monoisotopic mass is 3461.7377 Da.
How many compounds have the formula C143H244N50O42S4?
CompoundList lists 1 compound with the molecular formula C143H244N50O42S4, including Nesiritide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C143H244N50O42S4?
C143H244N50O42S4 has a degree of unsaturation of 47. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.