C148H211N68O53P13S13
1 compound has this formula on CompoundList.
- Molar mass
- 4610.18g/mol
- Monoisotopic mass
- 4606.8864Da
- Atoms
- 506
- Elements
- 6
- Rings plus double bonds
- 84
The formula C148H211N68O53P13S13 describes a molecule made of 148 carbon atoms, 211 hydrogen atoms, 68 nitrogen atoms, 53 oxygen atoms, 13 phosphorus atoms and 13 sulfur atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 14838.56%12.011 × 148 = 1777.628 g/mol
- H Hydrogen × 2114.61%1.008 × 211 = 212.688 g/mol
- N Nitrogen × 6820.66%14.007 × 68 = 952.476 g/mol
- O Oxygen × 5318.39%15.999 × 53 = 847.947 g/mol
- P Phosphorus × 138.73%30.974 × 13 = 402.662 g/mol
- S Sulfur × 139.04%32.06 × 13 = 416.780 g/mol
Compounds with the formula C148H211N68O53P13S13
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C148H211N68O53P13S13?
The molar mass of C148H211N68O53P13S13 is 4610.18 g/mol, calculated from standard atomic weights for 148 carbon atoms, 211 hydrogen atoms, 68 nitrogen atoms, 53 oxygen atoms, 13 phosphorus atoms and 13 sulfur atoms. The monoisotopic mass is 4606.8864 Da.
How many compounds have the formula C148H211N68O53P13S13?
CompoundList lists 1 compound with the molecular formula C148H211N68O53P13S13, including Imetelstat. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C148H211N68O53P13S13?
C148H211N68O53P13S13 has a degree of unsaturation of 84. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.