CompoundList
Molecular formula

C14H10BrFN2O3S

3 compounds have this formula on CompoundList.

Molar mass
385.21g/mol
Monoisotopic mass
383.9580Da
Atoms
32
Elements
7
Rings plus double bonds
10

The formula C14H10BrFN2O3S describes a molecule made of 14 carbon atoms, 10 hydrogen atoms, 1 bromine atom, 1 fluorine atom, 2 nitrogen atoms, 3 oxygen atoms and 1 sulfur atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1443.65%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 102.62%
    1.008 × 10 = 10.080 g/mol
  • Br Bromine × 120.74%
    79.904 × 1 = 79.904 g/mol
  • F Fluorine × 14.93%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 27.27%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 312.46%
    15.999 × 3 = 47.997 g/mol
  • S Sulfur × 18.32%
    32.06 × 1 = 32.060 g/mol
Look up another formula

Compounds with the formula C14H10BrFN2O3S

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Frequently asked questions

What is the molar mass of C14H10BrFN2O3S?

The molar mass of C14H10BrFN2O3S is 385.21 g/mol, calculated from standard atomic weights for 14 carbon atoms, 10 hydrogen atoms, 1 bromine atom, 1 fluorine atom, 2 nitrogen atoms, 3 oxygen atoms and 1 sulfur atom. The monoisotopic mass is 383.9580 Da.

How many compounds have the formula C14H10BrFN2O3S?

CompoundList lists 3 compounds with the molecular formula C14H10BrFN2O3S, including 2-[(4-Bromophenyl)sulfanyl]-N-(4-fluoro-3-nitrophenyl)acetamide, 1-(Benzo[d]isoxazol-3-yl)-N-(4-bromo-2-fluorophenyl)methanesulfonamide, 7-Bromo-9-cyclopropyl-6-fluoro-8-methoxy[1,2]thiazolo[5,4-b]quinoline-3,4(2H,9H)-dione. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H10BrFN2O3S?

C14H10BrFN2O3S has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.