Molecular formula

C₁₄H₁₀BrN₅O

17 compounds have this formula on CompoundList.

Molar mass: 344.17g/mol
Monoisotopic mass: 343.0069Da
Atoms: 31
Elements: 5
Rings plus double bonds: 12

The formula C14H10BrN5O describes a molecule made of 14 carbon atoms, 10 hydrogen atoms, 1 bromine atom, 5 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

C Carbon × 1448.86%
12.011 × 14 = 168.154 g/mol
H Hydrogen × 102.93%
1.008 × 10 = 10.080 g/mol
Br Bromine × 123.22%
79.904 × 1 = 79.904 g/mol
N Nitrogen × 520.35%
14.007 × 5 = 70.035 g/mol
O Oxygen × 14.65%
15.999 × 1 = 15.999 g/mol

Look up another formula

Compounds with the formula C14H10BrN5O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 17 of 17 compounds

5-(4-Bromophenyl)-7-(furan-2-yl)-4,7-dihydrotetrazolo[1,5-a]pyrimidine

CAS 487023-91-6C₁₄H₁₀BrN₅O

N-(4-Bromophenyl)-3-(1H-tetrazol-1-yl)benzamide

CAS 484039-66-9C₁₄H₁₀BrN₅O

N-(4-Bromophenyl)-4-(1H-tetrazol-1-yl)benzamide

CAS 332176-89-3C₁₄H₁₀BrN₅O

2-Bromo-N-[3-(1H-tetrazol-1-yl)phenyl]benzamide

CAS 883293-91-2C₁₄H₁₀BrN₅O

3-Bromo-N-[3-(1H-tetrazol-5-yl)phenyl]benzamide

CAS 915886-62-3C₁₄H₁₀BrN₅O

N-(3-Bromophenyl)-6-(1H-imidazol-1-yl)pyridazine-3-carboxamide

CAS 1396747-11-7C₁₄H₁₀BrN₅O

3-Bromo-N-[4-(1H-tetrazol-1-yl)phenyl]benzamide

CAS 852304-37-1C₁₄H₁₀BrN₅O

4-Bromo-N-[3-(1H-tetrazol-1-yl)phenyl]benzamide

CAS 901434-67-1C₁₄H₁₀BrN₅O

N-(3-Bromophenyl)-6-(1H-pyrazol-1-yl)pyridazine-3-carboxamide

CAS 1351642-20-0C₁₄H₁₀BrN₅O

3-Bromo-N-[3-(1H-tetrazol-1-yl)phenyl]benzamide

CAS 901432-14-2C₁₄H₁₀BrN₅O

N-(3-Bromophenyl)-3-(1H-tetrazol-1-yl)benzamide

CAS 1040714-08-6C₁₄H₁₀BrN₅O

N-(3-Bromophenyl)-4-(1H-tetrazol-1-yl)benzamide

CAS 1081123-53-6C₁₄H₁₀BrN₅O

4-Bromo-N-[2-(1H-tetrazol-1-yl)phenyl]benzamide

CAS 901323-99-7C₁₄H₁₀BrN₅O

3-Bromo-N-[2-(1H-tetrazol-1-yl)phenyl]benzamide

CAS 901435-50-5C₁₄H₁₀BrN₅O

9-Bromo-5,6-dihydro-5-phenyltetrazolo[1,5-c]quinazolin-5-ol

CAS 27398-51-2C₁₄H₁₀BrN₅O

2-Bromo-N-[1-(2-pyrimidinyl)-1H-pyrazol-3-yl]benzamide

CAS 1594626-78-4C₁₄H₁₀BrN₅O

2-(5-Bromo-1H-pyrazol-3-yl)-3,4-dihydro-3,8-dimethyl-4-oxo-6-quinazolinecarbonitrile

CAS 2411513-86-3C₁₄H₁₀BrN₅O

Frequently asked questions

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What is the molar mass of C14H10BrN5O?

The molar mass of C14H10BrN5O is 344.17 g/mol, calculated from standard atomic weights for 14 carbon atoms, 10 hydrogen atoms, 1 bromine atom, 5 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 343.0069 Da.

How many compounds have the formula C14H10BrN5O?

CompoundList lists 17 compounds with the molecular formula C14H10BrN5O, including 5-(4-Bromophenyl)-7-(furan-2-yl)-4,7-dihydrotetrazolo[1,5-a]pyrimidine, N-(4-Bromophenyl)-3-(1H-tetrazol-1-yl)benzamide, N-(4-Bromophenyl)-4-(1H-tetrazol-1-yl)benzamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H10BrN5O?

C14H10BrN5O has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.