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Molecular formula

C14H10F3N5

11 compounds have this formula on CompoundList.

Molar mass
305.26g/mol
Monoisotopic mass
305.0888Da
Atoms
32
Elements
4
Rings plus double bonds
11

The formula C14H10F3N5 describes a molecule made of 14 carbon atoms, 10 hydrogen atoms, 3 fluorine atoms and 5 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1455.08%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 103.30%
    1.008 × 10 = 10.080 g/mol
  • F Fluorine × 318.67%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 522.94%
    14.007 × 5 = 70.035 g/mol
Look up another formula

Compounds with the formula C14H10F3N5

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 11 of 11 compounds

4-Methyl-2-(4-phenyl-1H-1,2,3-triazol-1-yl)-6-(trifluoromethyl)pyrimidine chemical structure, C14H10F3N5, CAS 860612-50-6
4-Methyl-2-(4-phenyl-1H-1,2,3-triazol-1-yl)-6-(trifluoromethyl)pyrimidine
CAS 860612-50-6C14H10F3N5
N-(4H-1,2,4-Triazol-4-yl)-N-({1-[3-(trifluoromethyl)phenyl]-1H-pyrrol-2-yl}methylene)amine chemical structure, C14H10F3N5, CAS 664350-24-7
N-(4H-1,2,4-Triazol-4-yl)-N-({1-[3-(trifluoromethyl)phenyl]-1H-pyrrol-2-yl}methylene)amine
CAS 664350-24-7C14H10F3N5
2-(1H-Tetrazol-5-yl)-N-(3-(trifluoromethyl)phenyl)aniline chemical structure, C14H10F3N5, CAS 13481-63-5
2-(1H-Tetrazol-5-yl)-N-(3-(trifluoromethyl)phenyl)aniline
CAS 13481-63-5C14H10F3N5
4-N-[2-(Trifluoromethyl)phenyl]pyrido[4,3-d]pyrimidine-4,7-diamine chemical structure, C14H10F3N5, CAS 171178-79-3
4-N-[2-(Trifluoromethyl)phenyl]pyrido[4,3-d]pyrimidine-4,7-diamine
CAS 171178-79-3C14H10F3N5
4-N-[3-(Trifluoromethyl)phenyl]pyrido[4,3-d]pyrimidine-4,7-diamine chemical structure, C14H10F3N5, CAS 171178-80-6
4-N-[3-(Trifluoromethyl)phenyl]pyrido[4,3-d]pyrimidine-4,7-diamine
CAS 171178-80-6C14H10F3N5
4-N-[4-(Trifluoromethyl)phenyl]pyrido[4,3-d]pyrimidine-4,7-diamine chemical structure, C14H10F3N5, CAS 171178-81-7
4-N-[4-(Trifluoromethyl)phenyl]pyrido[4,3-d]pyrimidine-4,7-diamine
CAS 171178-81-7C14H10F3N5
6-Methyl-1-(1-methyl-1H-pyrazol-4-yl)-4-(trifluoromethyl)-1H-pyrrolo[2,3-b]pyridine-3-carbonitrile chemical structure, C14H10F3N5, CAS 1171712-34-7
6-Methyl-1-(1-methyl-1H-pyrazol-4-yl)-4-(trifluoromethyl)-1H-pyrrolo[2,3-b]pyridine-3-carbonitrile
CAS 1171712-34-7C14H10F3N5
5-Hydrazinyl-2-phenyl-3-(trifluoromethyl)pyrido[3,4-b]pyrazine chemical structure, C14H10F3N5, CAS 877402-56-7
5-Hydrazinyl-2-phenyl-3-(trifluoromethyl)pyrido[3,4-b]pyrazine
CAS 877402-56-7C14H10F3N5
2-[2-[3-Methyl-5-(trifluoromethyl)phenyl]tetrazol-5-yl]pyridine chemical structure, C14H10F3N5, CAS 507268-54-4
2-[2-[3-Methyl-5-(trifluoromethyl)phenyl]tetrazol-5-yl]pyridine
CAS 507268-54-4C14H10F3N5
2-[(S)-Phenyl(1H-1,2,3,4-tetrazol-5-yl)methyl]-3-(trifluoromethyl)pyridine chemical structure, C14H10F3N5, CAS 2085690-67-9
2-[(S)-Phenyl(1H-1,2,3,4-tetrazol-5-yl)methyl]-3-(trifluoromethyl)pyridine
CAS 2085690-67-9C14H10F3N5
3-Phenyl-1-[4-(trifluoromethyl)pyrimidin-2-yl]-1H-pyrazol-5-amine chemical structure, C14H10F3N5, CAS 608144-25-8
3-Phenyl-1-[4-(trifluoromethyl)pyrimidin-2-yl]-1H-pyrazol-5-amine
CAS 608144-25-8C14H10F3N5

Frequently asked questions

What is the molar mass of C14H10F3N5?

The molar mass of C14H10F3N5 is 305.26 g/mol, calculated from standard atomic weights for 14 carbon atoms, 10 hydrogen atoms, 3 fluorine atoms and 5 nitrogen atoms. The monoisotopic mass is 305.0888 Da.

How many compounds have the formula C14H10F3N5?

CompoundList lists 11 compounds with the molecular formula C14H10F3N5, including 4-Methyl-2-(4-phenyl-1H-1,2,3-triazol-1-yl)-6-(trifluoromethyl)pyrimidine, N-(4H-1,2,4-Triazol-4-yl)-N-({1-[3-(trifluoromethyl)phenyl]-1H-pyrrol-2-yl}methylene)amine, 2-(1H-Tetrazol-5-yl)-N-(3-(trifluoromethyl)phenyl)aniline. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H10F3N5?

C14H10F3N5 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.