C14H14BrI
1 compound has this formula on CompoundList.
- Molar mass
- 389.07g/mol
- Monoisotopic mass
- 387.9324Da
- Atoms
- 30
- Elements
- 4
- Rings plus double bonds
- 7
The formula C14H14BrI describes a molecule made of 14 carbon atoms, 14 hydrogen atoms, 1 bromine atom and 1 iodine atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1443.22%12.011 × 14 = 168.154 g/mol
- H Hydrogen × 143.63%1.008 × 14 = 14.112 g/mol
- Br Bromine × 120.54%79.904 × 1 = 79.904 g/mol
- I Iodine × 132.62%126.9 × 1 = 126.900 g/mol
Compounds with the formula C14H14BrI
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 1 of 1 compounds
Frequently asked questions
What is the molar mass of C14H14BrI?
The molar mass of C14H14BrI is 389.07 g/mol, calculated from standard atomic weights for 14 carbon atoms, 14 hydrogen atoms, 1 bromine atom and 1 iodine atom. The monoisotopic mass is 387.9324 Da.
How many compounds have the formula C14H14BrI?
CompoundList lists 1 compound with the molecular formula C14H14BrI, including Iodonium, bis(4-methylphenyl)-, bromide (1:1). Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C14H14BrI?
C14H14BrI has a degree of unsaturation of 7. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.