C14H15ClN2O4
48 compounds have this formula on CompoundList.
- Molar mass
- 310.73g/mol
- Monoisotopic mass
- 310.0720Da
- Atoms
- 36
- Elements
- 5
- Rings plus double bonds
- 8
The formula C14H15ClN2O4 describes a molecule made of 14 carbon atoms, 15 hydrogen atoms, 1 chlorine atom, 2 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1454.12%12.011 × 14 = 168.154 g/mol
- H Hydrogen × 154.87%1.008 × 15 = 15.120 g/mol
- Cl Chlorine × 111.41%35.45 × 1 = 35.450 g/mol
- N Nitrogen × 29.02%14.007 × 2 = 28.014 g/mol
- O Oxygen × 420.60%15.999 × 4 = 63.996 g/mol
Compounds with the formula C14H15ClN2O4
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 48 of 48 compounds
- 3-[2-(2-Nitrophenoxy)ethoxy]aniline--hydrogen chloride (1/1)19157-77-8C14H15ClN2O4
- Methyl 4-(2-chloro-3-methoxyphenyl)-6-methyl-2-oxo-1,2,3,4-tetrahydro-5-pyrimidinecarboxylate853328-48-0C14H15ClN2O4
- 1-(5-Chloro-2-methylphenyl)-3-(ethoxycarbonyl)-4,5-dihydro-1H-pyrazole-5-carboxylic acid1264041-75-9C14H15ClN2O4
- 1-(3-Chloro-4-methylphenyl)-3-(ethoxycarbonyl)-4,5-dihydro-1H-pyrazole-5-carboxylic acid1264042-92-3C14H15ClN2O4
- 1-(3-Chloro-2-methylphenyl)-3-(ethoxycarbonyl)-4,5-dihydro-1H-pyrazole-5-carboxylic acid1264042-79-6C14H15ClN2O4
- 1-(3-Chlorophenyl)-3-(ethoxycarbonyl)-5-methyl-4,5-dihydro-1H-pyrazole-5-carboxylic acid1264044-19-0C14H15ClN2O4
- Methyl 1-[2-(4-chlorophenyl)-2-hydroxyethyl]-5-(hydroxymethyl)-1H-imidazole-4-carboxylate1984183-51-8C14H15ClN2O4
- 4-{[5-(Butyrylamino)-2-chlorophenyl]amino}-4-oxo-2-butenoic acid940106-84-3C14H15ClN2O4
- 2-Chloro-N-(1-((1,3-dioxoisoindolin-2-yl)oxy)-2-methylpropan-2-yl)acetamide953773-67-6C14H15ClN2O4
- 1-(4-Chlorophenyl)-3-(ethoxycarbonyl)-5-methyl-4,5-dihydro-1H-pyrazole-5-carboxylic acid1264048-83-0C14H15ClN2O4
- 1-(2-Chlorophenyl)-3-(ethoxycarbonyl)-5-methyl-4,5-dihydro-1H-pyrazole-5-carboxylic acid1264046-73-2C14H15ClN2O4
- Ethyl N-[(2Z)-2-{[(4-chlorophenyl)amino]methylidene}-3-oxobutanoyl]carbamateC14H15ClN2O4
- Ethyl N-[(Z)-2-[(4-chlorophenyl)iminomethyl]-3-hydroxybut-2-enoyl]carbamateC14H15ClN2O4
- 5-Chloro-3-[3-(morpholin-4-yl)-2-oxopropyl]-1,3-benzoxazol-2(3H)-one62104-01-2C14H15ClN2O4
- Ethyl 5-chloro-3-(2-ethoxy-2-oxoethyl)-1H-indazole-1-carboxylate88561-99-3C14H15ClN2O4
- 1,2,3,5,6,11-Hexahydroindolizino[8,7-b]indol-4-ium perchlorate88115-10-0C14H15ClN2O4
- 5-{[(6-Chloro-7-methyl-2-oxo-2H-indol-3-yl)amino]oxy}pentanoic acid1202859-08-2C14H15ClN2O4
- 1-[2-(tert-Butoxy)-2-oxoethyl]-6-chloro-1H-pyrrolo[2,3-b]pyridine-3-carboxylic acid2803859-51-8C14H15ClN2O4
- 2-{[(tert-Butoxy)carbonyl](prop-2-yn-1-yl)amino}-6-chloropyridine-3-carboxylic acid2639447-85-9C14H15ClN2O4
- Ethyl 4-[(4-amino-2-chlorophenoxy)methyl]-5-methyl-1,2-oxazole-3-carboxylate2639459-03-1C14H15ClN2O4
- 1-tert-Butyl 7-methyl 6-chloro-1H-indazole-1,7-dicarboxylate2680856-99-7C14H15ClN2O4
- 1-[(tert-Butoxy)carbonyl]-4-chloro-3-methyl-1H-indazole-5-carboxylic acid2680869-31-0C14H15ClN2O4
- 2-{[(tert-Butoxy)carbonyl]amino}-6-chloro-1H-indole-3-carboxylic acid2920116-83-0C14H15ClN2O4
- 5-[(E)-(6-Chloro-7-methyl-2-oxo-1H-indol-3-ylidene)amino]oxypentanoic acidC14H15ClN2O4
Frequently asked questions
What is the molar mass of C14H15ClN2O4?
The molar mass of C14H15ClN2O4 is 310.73 g/mol, calculated from standard atomic weights for 14 carbon atoms, 15 hydrogen atoms, 1 chlorine atom, 2 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 310.0720 Da.
How many compounds have the formula C14H15ClN2O4?
CompoundList lists 48 compounds with the molecular formula C14H15ClN2O4, including 2-[[1-(4-Chlorophenyl)-2,5-dioxo-3-pyrrolidinyl]-methylamino]acetic acid methyl ester, N,N'-(2-Chloro-1,4-phenylene)bis(3-oxobutaneamide), Ethyl 5-{[(2-chlorobenzoyl)amino]methyl}-4,5-dihydro-3-isoxazolecarboxylate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C14H15ClN2O4?
C14H15ClN2O4 has a degree of unsaturation of 8. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.