CompoundList
Molecular formula

C14H18BF4N3

2 compounds have this formula on CompoundList.

Molar mass
315.12g/mol
Monoisotopic mass
315.1530Da
Atoms
40
Elements
5

The formula C14H18BF4N3 describes a molecule made of 14 carbon atoms, 18 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 3 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1453.36%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 185.76%
    1.008 × 18 = 18.144 g/mol
  • B Boron × 13.43%
    10.81 × 1 = 10.810 g/mol
  • F Fluorine × 424.12%
    18.998 × 4 = 75.992 g/mol
  • N Nitrogen × 313.33%
    14.007 × 3 = 42.021 g/mol
Look up another formula

Compounds with the formula C14H18BF4N3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 2 of 2 compounds

Frequently asked questions

What is the molar mass of C14H18BF4N3?

The molar mass of C14H18BF4N3 is 315.12 g/mol, calculated from standard atomic weights for 14 carbon atoms, 18 hydrogen atoms, 1 boron atom, 4 fluorine atoms and 3 nitrogen atoms. The monoisotopic mass is 315.1530 Da.

How many compounds have the formula C14H18BF4N3?

CompoundList lists 2 compounds with the molecular formula C14H18BF4N3, including 2-Mesityl-6,7-dihydro-5H-pyrrolo(2,1-c)(1,2,4)triazol-2-ium tetrafluoroborate, (R)-5-Isopropyl-2-phenyl-6,7-dihydro-5H-pyrrolo[2,1-c][1,2,4]triazol-2-ium tetrafluoroborate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.