C14H19IO3
13 compounds have this formula on CompoundList.
- Molar mass
- 362.20g/mol
- Monoisotopic mass
- 362.0379Da
- Atoms
- 37
- Elements
- 4
- Rings plus double bonds
- 5
The formula C14H19IO3 describes a molecule made of 14 carbon atoms, 19 hydrogen atoms, 1 iodine atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1446.43%12.011 × 14 = 168.154 g/mol
- H Hydrogen × 195.29%1.008 × 19 = 19.152 g/mol
- I Iodine × 135.04%126.9 × 1 = 126.900 g/mol
- O Oxygen × 313.25%15.999 × 3 = 47.997 g/mol
Compounds with the formula C14H19IO3
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 13 of 13 compounds
![Ethyl 2-[(4-iodophenyl)methyl]butyl carbonate chemical structure, C14H19IO3, CAS 60075-85-6](/s/GJRWVOILYYUZOG-UHFFFAOYSA-N.svg)
![Ethyl 1-({3-iodobicyclo[1.1.1]pentan-1-yl}methyl)-2-oxabicyclo[2.1.1]hexane-4-carboxylate chemical structure, C14H19IO3, CAS 2758002-72-9](/s/RVYJMWZKHPGHHX-UHFFFAOYSA-N.svg)
![{[2-(1-Ethoxyethoxy)-4-iodobut-3-en-1-yl]oxy}benzene chemical structure, C14H19IO3, CAS 90157-03-2](/s/ZOICNKLVZXNGQC-UHFFFAOYSA-N.svg)
Frequently asked questions
What is the molar mass of C14H19IO3?
The molar mass of C14H19IO3 is 362.20 g/mol, calculated from standard atomic weights for 14 carbon atoms, 19 hydrogen atoms, 1 iodine atom and 3 oxygen atoms. The monoisotopic mass is 362.0379 Da.
How many compounds have the formula C14H19IO3?
CompoundList lists 13 compounds with the molecular formula C14H19IO3, including 1-(2-Hydroxy-4-(3-iodopropoxy)-3-propylphenyl)ethanone, Carbonic acid, 1-ethylbutyl p-iodobenzyl ester, Carbonic acid, hexyl p-iodobenzyl ester. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C14H19IO3?
C14H19IO3 has a degree of unsaturation of 5. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.