C14H23Cl2N3O
34 compounds have this formula on CompoundList.
- Molar mass
- 320.26g/mol
- Monoisotopic mass
- 319.1218Da
- Atoms
- 43
- Elements
- 5
- Rings plus double bonds
- 4
The formula C14H23Cl2N3O describes a molecule made of 14 carbon atoms, 23 hydrogen atoms, 2 chlorine atoms, 3 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.
Elemental composition
- C Carbon × 1452.51%12.011 × 14 = 168.154 g/mol
- H Hydrogen × 237.24%1.008 × 23 = 23.184 g/mol
- Cl Chlorine × 222.14%35.45 × 2 = 70.900 g/mol
- N Nitrogen × 313.12%14.007 × 3 = 42.021 g/mol
- O Oxygen × 15.00%15.999 × 1 = 15.999 g/mol
Compounds with the formula C14H23Cl2N3O
Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.
Showing 1 to 34 of 34 compounds
- 1-Isopropyl-4,6-dihydrospiro[indazole-5,4'-piperidin]-7(1H)-one dihydrochloride1384265-02-4C14H23Cl2N3O
- 4-Amino-2-chloro-N-[3-(diethylamino)propyl]benzamide hydrochloride1421604-06-9C14H23Cl2N3O
- N-(2,3-Dimethylphenyl)-2-(piperazin-1-yl)acetamide dihydrochloride2033750-35-3C14H23Cl2N3O
- Benzamidine, 4-methoxy-N-(2-(1-pyrrolidinyl)ethyl)-, dihydrochloride, hydrate73688-82-1C14H23Cl2N3O
- (4-(Aminomethyl)phenyl)(4-ethylpiperazin-1-yl)methanone dihydrochloride1587112-32-0C14H23Cl2N3O
- N-(2,6-Dimethylphenyl)-2-(piperazin-1-yl)acetamide dihydrochloride3398-91-2C14H23Cl2N3O
- Lys-isoindoline dihydrochloride salt1279032-38-0C14H23Cl2N3O
- 3-Amino-1-[4-(3-methylphenyl)piperazin-1-yl]propan-1-one dihydrochloride1577145-19-7C14H23Cl2N3O
- 1-Benzoyl-2-[(4RS)-1-methylhexahydro-1H-azepin-4-yl]diazane Dihydrochloride2731998-18-6C14H23Cl2N3O
- (S)-(4-(1-Aminoethyl)phenyl)(4-methylpiperazin-1-yl)methanone dihydrochloride2990243-09-7C14H23Cl2N3O
Frequently asked questions
What is the molar mass of C14H23Cl2N3O?
The molar mass of C14H23Cl2N3O is 320.26 g/mol, calculated from standard atomic weights for 14 carbon atoms, 23 hydrogen atoms, 2 chlorine atoms, 3 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 319.1218 Da.
How many compounds have the formula C14H23Cl2N3O?
CompoundList lists 34 compounds with the molecular formula C14H23Cl2N3O, including N-(4-Pyridyl)-4-(1-aminoethyl)cyclohexanecarboxamide dihydrochloride, Y-27632 dihydrochloride, N-(2-(Dimethylamino)ethyl)-1,2,3,4-tetrahydroisoquinoline-3-carboxamide dihydrochloride. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.
What is the degree of unsaturation of C14H23Cl2N3O?
C14H23Cl2N3O has a degree of unsaturation of 4. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.