CompoundList
Molecular formula

C14H28BNO4

3 compounds have this formula on CompoundList.

Molar mass
285.19g/mol
Monoisotopic mass
285.2111Da
Atoms
48
Elements
5

The formula C14H28BNO4 describes a molecule made of 14 carbon atoms, 28 hydrogen atoms, 1 boron atom, 1 nitrogen atom and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1458.96%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 289.90%
    1.008 × 28 = 28.224 g/mol
  • B Boron × 13.79%
    10.81 × 1 = 10.810 g/mol
  • N Nitrogen × 14.91%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 422.44%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C14H28BNO4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 3 of 3 compounds

Frequently asked questions

What is the molar mass of C14H28BNO4?

The molar mass of C14H28BNO4 is 285.19 g/mol, calculated from standard atomic weights for 14 carbon atoms, 28 hydrogen atoms, 1 boron atom, 1 nitrogen atom and 4 oxygen atoms. The monoisotopic mass is 285.2111 Da.

How many compounds have the formula C14H28BNO4?

CompoundList lists 3 compounds with the molecular formula C14H28BNO4, including tert-Butyl N-[3-(tetramethyl-1,3,2-dioxaborolan-2-yl)propyl]carbamate, tert-Butyl N-(1-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)propan-2-yl)carbamate, tert-Butyl N-[2-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)propyl]carbamate. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.