CompoundList
Molecular formula

C14H7NO3

9 compounds have this formula on CompoundList.

Molar mass
237.21g/mol
Monoisotopic mass
237.0426Da
Atoms
25
Elements
4
Rings plus double bonds
12

The formula C14H7NO3 describes a molecule made of 14 carbon atoms, 7 hydrogen atoms, 1 nitrogen atom and 3 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1470.89%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 72.97%
    1.008 × 7 = 7.056 g/mol
  • N Nitrogen × 15.90%
    14.007 × 1 = 14.007 g/mol
  • O Oxygen × 320.23%
    15.999 × 3 = 47.997 g/mol
Look up another formula

Compounds with the formula C14H7NO3

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 9 of 9 compounds

Frequently asked questions

What is the molar mass of C14H7NO3?

The molar mass of C14H7NO3 is 237.21 g/mol, calculated from standard atomic weights for 14 carbon atoms, 7 hydrogen atoms, 1 nitrogen atom and 3 oxygen atoms. The monoisotopic mass is 237.0426 Da.

How many compounds have the formula C14H7NO3?

CompoundList lists 9 compounds with the molecular formula C14H7NO3, including 5H-Furo(3',2':6,7)(1)benzopyrano(3,4-c)pyridin-5-one, 1H-[1]Benzofuro[3,2-f]indole-2,3-dione, 1H-Benzofuro[2,3-f]indole-2,3-dione. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H7NO3?

C14H7NO3 has a degree of unsaturation of 12. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.