CompoundList
Molecular formula

C14H9F2N3O

13 compounds have this formula on CompoundList.

Molar mass
273.24g/mol
Monoisotopic mass
273.0714Da
Atoms
29
Elements
5
Rings plus double bonds
11

The formula C14H9F2N3O describes a molecule made of 14 carbon atoms, 9 hydrogen atoms, 2 fluorine atoms, 3 nitrogen atoms and 1 oxygen atom. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1461.54%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 93.32%
    1.008 × 9 = 9.072 g/mol
  • F Fluorine × 213.91%
    18.998 × 2 = 37.996 g/mol
  • N Nitrogen × 315.38%
    14.007 × 3 = 42.021 g/mol
  • O Oxygen × 15.86%
    15.999 × 1 = 15.999 g/mol
Look up another formula

Compounds with the formula C14H9F2N3O

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 13 of 13 compounds

Frequently asked questions

What is the molar mass of C14H9F2N3O?

The molar mass of C14H9F2N3O is 273.24 g/mol, calculated from standard atomic weights for 14 carbon atoms, 9 hydrogen atoms, 2 fluorine atoms, 3 nitrogen atoms and 1 oxygen atom. The monoisotopic mass is 273.0714 Da.

How many compounds have the formula C14H9F2N3O?

CompoundList lists 13 compounds with the molecular formula C14H9F2N3O, including N-(1H-Benzimidazol-2-yl)-3,5-difluorobenzamide, 5-(3,4-Difluorophenyl)-3-(6-methylpyridin-3-yl)-1,2,4-oxadiazole, N-(3,4-Difluorophenyl)-1H-indazole-5-carboxamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H9F2N3O?

C14H9F2N3O has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.