CompoundList
Molecular formula

C14H9F3N2O4

13 compounds have this formula on CompoundList.

Molar mass
326.23g/mol
Monoisotopic mass
326.0514Da
Atoms
32
Elements
5
Rings plus double bonds
10

The formula C14H9F3N2O4 describes a molecule made of 14 carbon atoms, 9 hydrogen atoms, 3 fluorine atoms, 2 nitrogen atoms and 4 oxygen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1451.54%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 92.78%
    1.008 × 9 = 9.072 g/mol
  • F Fluorine × 317.47%
    18.998 × 3 = 56.994 g/mol
  • N Nitrogen × 28.59%
    14.007 × 2 = 28.014 g/mol
  • O Oxygen × 419.62%
    15.999 × 4 = 63.996 g/mol
Look up another formula

Compounds with the formula C14H9F3N2O4

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 13 of 13 compounds

Frequently asked questions

What is the molar mass of C14H9F3N2O4?

The molar mass of C14H9F3N2O4 is 326.23 g/mol, calculated from standard atomic weights for 14 carbon atoms, 9 hydrogen atoms, 3 fluorine atoms, 2 nitrogen atoms and 4 oxygen atoms. The monoisotopic mass is 326.0514 Da.

How many compounds have the formula C14H9F3N2O4?

CompoundList lists 13 compounds with the molecular formula C14H9F3N2O4, including 4-Nitro-N-[2-(trifluoromethoxy)phenyl]benzamide, 4-Nitro-2-{[3-(trifluoromethyl)phenyl]amino}benzoic acid, 4-Nitro-N-[4-(trifluoromethoxy)phenyl]benzamide. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H9F3N2O4?

C14H9F3N2O4 has a degree of unsaturation of 10. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.