CompoundList
Molecular formula

C14H9FN2

19 compounds have this formula on CompoundList.

Molar mass
224.24g/mol
Monoisotopic mass
224.0750Da
Atoms
26
Elements
4
Rings plus double bonds
11

The formula C14H9FN2 describes a molecule made of 14 carbon atoms, 9 hydrogen atoms, 1 fluorine atom and 2 nitrogen atoms. It is written in Hill notation: carbon first, then hydrogen, then the other elements in alphabetical order. The formula tells you which atoms are present, not how they are connected, which is why several different chemicals can share it.

Elemental composition

  • C Carbon × 1474.99%
    12.011 × 14 = 168.154 g/mol
  • H Hydrogen × 94.05%
    1.008 × 9 = 9.072 g/mol
  • F Fluorine × 18.47%
    18.998 × 1 = 18.998 g/mol
  • N Nitrogen × 212.49%
    14.007 × 2 = 28.014 g/mol
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Compounds with the formula C14H9FN2

Isomers we list, best known first. Open one to see its structure, properties, safety data and suppliers.

Showing 1 to 19 of 19 compounds

Frequently asked questions

What is the molar mass of C14H9FN2?

The molar mass of C14H9FN2 is 224.24 g/mol, calculated from standard atomic weights for 14 carbon atoms, 9 hydrogen atoms, 1 fluorine atom and 2 nitrogen atoms. The monoisotopic mass is 224.0750 Da.

How many compounds have the formula C14H9FN2?

CompoundList lists 19 compounds with the molecular formula C14H9FN2, including 2-(4-Fluorophenyl)quinoxaline, 2-(2-Fluorophenyl)-1,8-naphthyridine, (2Z)-3-(4-Fluorophenyl)-2-(2-pyridyl)prop-2-enenitrile. Compounds that share a formula are isomers. They contain the same atoms arranged differently, so their properties, uses and prices can be very different.

What is the degree of unsaturation of C14H9FN2?

C14H9FN2 has a degree of unsaturation of 11. That is the total number of rings and pi bonds (a double bond counts as one, a triple bond as two) in any structure with this formula.